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Q.

An ungraduated thermometer of uniform bore is attached to a centimeter scale and is found to read 10.3 cm in melting ice, 26.8 cm in boiling water and 6.5 cm in freezing mixture. The temperature of the freezing mixture is $- {(20.03 + x)}^{o} C$ , then the value of $' x'$ is

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answer is 3.

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Detailed Solution

Based on proportionation factors 10.3 cm to 2.8 cm are divided into 100 equal divisions
1division = $1^{o} C$
$16.5 c m \to 100^{o} c$
$1 c m \to 1 c m = {\frac{100}{16.5}}^{o} C$
Given devision 10.3 cm – 6.5 cm
=3.5 cm
$\Rightarrow (\frac{100}{16.5}) {(3.5)}^{o} C = - {23.03}^{o} C$

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An ungraduated thermometer of uniform bore is attached to a centimeter scale and is found to read 10.3 cm in melting ice, 26.8 cm in boiling water and 6.5 cm in freezing mixture. The temperature of the freezing mixture is −20.03+xoC , then the value of 'x' is