An unknown compound A has been prepared from the reaction of dehalogenation of a tetra halo derivative with zinc and B is its positional isomer. B gives a white precipitate with ammoniacal Silver nitrate but not A. A and B maybe

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${CH}_{3} {CH}_{2} C \equiv {CH (A) and CH}_{3} C \equiv {CCH}_{3} (B)$

${CH}_{3} C \equiv {CCH}_{3} {(A) and CH}_{3} {CH}_{2} C \equiv CH (B)$

${CH}_{3} CH = C = {CH}_{2} {(A) and CH}_{3} C \equiv {CCH}_{3} (B)$

${CH}_{3} CH = C = {CH}_{2} {(A) and CH}_{3} {CH}_{2} C \equiv CH (B)$

answer is B.

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Detailed Solution

[Step 1]: dehalogenation of tetra halo derivative with zinc will give alkyne or dienes
[Step 2]: Terminal Alkynes gives white precipitate with ammoniacal Silver nitrate whereas internal Alkynes won’t. It indicates that A is internal alkyne and B is terminal alkyne

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