An unknown hydrocarbon of the formula $C_{8} H_{14} (A)$ on reaction with excess $H_{2} / N i$ produces 1-ethyl-2-methylcyclopentane. Compound ‘A’ react with $B r_{2} / C C l_{4}$ ‘A’ on reductive ozonolysis forms the following major product (B)
Which of the following statement(s) are true regarding above information?

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

Number of optically active Isomers for A (including itself) are ‘4’

Compound ‘A’ is 3-ethyl-4-methyl cyclopentene

Compound ‘A’ is 1-ethyl-2-methylcyclopentene

Compound ‘A’ is 3-ethyl-5-methyl cyclopentene

answer is A, D.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

‘A’ has two chiral centers \no.of optically active isomers, For A are, $2^{2} = 4$

Watch 3-min video & get full concept clarity

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test