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An urn contains 81 marbles each of which is white black or green. The probability of selecting a white marble at random from the urn is $13$ and the probability of selecting a black marble at random is $49$ and the probability of selecting a black marble at random is . How many green marbles does the urn contain?

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answer is D.

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Detailed Solution

Given that there are 81 marbles.
Probability of selecting white is

13

.
Probability of selecting black is

49

.
According to the question,

P g r e e n = 1 − P b l a c k + P w h i t e = 1 − 13 + 49 = 29

Therefore,

Number of green marbles = total number of marbles P (green) = 8129 = 18

Number of green marbles = 18.
Hence, option 4 is correct.

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