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Analysis of a compound yields the following percentage composition. $65.03 %$ of $A g$ ; $15.68 % C r; 19.29 % O$ . The simplest formula of the compound is [Cr At.wt=52]

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${A g}_{2} {C r O}_{4}$

${A g}_{2} {C r}_{2} O_{7}$

${A g C r O}_{2}$

${A g C r}_{2} O_{3}$

answer is A.

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Detailed Solution

To find the simplest formula, we first divide the percentage composition by the atomic weight of that element, then divide the result by the smallest of the three values obtained.

Element	Ag	Cr	O
mass	65.03	15.68	19.29
No. of atoms	65.03/108=0.6	15.68/52=0.3	19.29/16=1.2
Relative no. of atoms	0.6/0.3=2	0.3/0.3=1	1.2/0.3=4

So, the simplest formula of the compound is ${A g}_{2} {C r O}_{4}$ .

Hence, option (A) is correct.

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