Analysis of chlorophyll shows that it contains $2.68 % M g$ . Number of magnesium atoms present in $2.4 g$ of chlorophyll is

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$2.68 \times 6 \times 10^{20}$

$2.68 \times 6 \times 10^{21}$

$2.68 \times 6 \times 10^{23}$

$2.68 \times 6 \times 10^{20} / 24$

answer is C.

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Detailed Solution

Let us consider 100g chlorophyll

This implies 100g will contain 2.68g magnesium in it

Then 2.4 g chlorophyll contains- $2.68 \times 2.4 / 100$ g magnesium

Moles of magnesium= $2.68 \times 2.4 / 100 \times 24$ = $2.68 / 1000$ moles

Now one mole= $N_{0} = 6.022$ $\times 10^{23}$ i.e., Avogadro's number entities

Using this fact $2.68 / 1000$ moles contains $2 \cdot 68 \times 6 \times 10^{20}$ magnesium atoms

Hence option(C) is the correct answer.

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