Analysis shows that nickel oxide has formula  $N{i}_{0.98}{O}_{1.00}$ the % of $N{i}^{3+}$ is  $X\%$ then $\text{'}x\text{'}$ is _________

$N{i}_{0.98}{O}_{1.00}\left(or\right)N{i}_{98}{O}_{100}$

$N{i}^{+3}=x;N{i}^{+2}=(98-x)$

$X(+3)+(98-X)(+2)-200=0$

$x+196-200=0$

$\therefore x=4$ for $98gm$ of $Ni\to 4N{i}^{+3}$

for $100gram$ atom $\to ?=4.08$