Angle of minimum deviation for a prism of refractive index 1.5 is equal to the angle of prism. The angle of prism is (cos 41° = 0.75)

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62°

82°

41°

31°

answer is C.

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Detailed Solution

$By prism formula n = \frac{\sin \frac{A + A}{2}}{\sin \frac{A}{2}} = \frac{2 \sin \frac{A}{2} \cos \frac{A}{2}}{\sin \frac{A}{2}} ∴ \cos \frac{A}{2} = \frac{n}{2} = \frac{1 .5}{2} = 0 .75 = \cos 41^{\circ} \Rightarrow A = 82^{\circ}$

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