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Q.

Angular part of wave function for an orbital is  =(154π)1/2Sinθ  Cosθ  Sinϕ
And its alternative form is  =(154π)1/2Sin(2θ)2  Sinϕ
Where  θ=angle with Z-axis,  ϕis the angle with X-axis. Then correct statement(s) about the orbital is/are
 

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a

XY – plane is nodal plane

b

YZ – plane is nodal plane

c

XZ – plane is nodal plane

d

It could be dyz  orbital

answer is A, C, D.

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Detailed Solution

Angular part of wave function is zero for nodel plane 
1) If θ=0°,  ϕ=0°  then angular part  =0
  xzplane
2) If θ=90,  ϕ=0°  then angular part  =0
  xyplane
 

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Angular part of wave function for an orbital is  =(154π)1/2Sinθ  Cosθ  SinϕAnd its alternative form is  =(154π)1/2Sin(2θ)2  SinϕWhere  θ=angle with Z-axis,  ϕ−is the angle with X-axis. Then correct statement(s) about the orbital is/are