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Angular width of the central maxima in the Fraunhofer diffraction for $λ = 6000 \overset{0}{A} is θ_{0} .$ When the same slit is illuminated by another monochromatic light, the angular width decreases by 30%. The wavelength of this light is,

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$1800 Å$

4200 Å

6000 Å

420 Å

answer is B.

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Detailed Solution

$θ$ has to become $0.7 θ$
$λ$ has to become $\frac{70}{100} λ$

$λ^{1} = \frac{70}{100} \times 6000 = 4200 A^{\circ}$

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