Aniline is oxidized with K2Cr2O7 / H2SO4. The product formed is _______

Answer: The product formed is para-benzoquinone (p-benzoquinone).Explanation:Aniline (C6H5NH2) undergoes oxidation with acidified potassium dichromate.During the reaction, the amino group (-NH2) is converted into carbonyl groups (=O) at the para positions of the benzene ring.This results in the formation of para-benzoquinone (C6H4O2), a benzene ring with two oppositely located carbonyl functional groups.Product structure: Benzene ring with two ketone groups at the para positions.

Aniline is oxidized with K2Cr2O7 / H2SO4. The product formed is _______

Answer: The product formed is para-benzoquinone (p-benzoquinone).Explanation:Aniline (C6H5NH2) undergoes oxidation with acidified potassium dichromate.During the reaction, the amino group (-NH2) is converted into carbonyl groups (=O) at the para positions of the benzene ring.This results in the formation of para-benzoquinone (C6H4O2), a benzene ring with two oppositely located carbonyl functional groups.Product structure: Benzene ring with two ketone groups at the para positions.

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Aniline is oxidized with K₂Cr₂O₇ / H₂SO₄. The product formed is _______

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Nitrosobenzene

Nitrobenzene

p–benzoquinone

Phenyl hydrozylamine

answer is B.

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Detailed Solution

Answer: The product formed is para-benzoquinone (p-benzoquinone).

Explanation:

Aniline (C₆H₅NH₂) undergoes oxidation with acidified potassium dichromate.
During the reaction, the amino group (-NH₂) is converted into carbonyl groups (=O) at the para positions of the benzene ring.
This results in the formation of para-benzoquinone (C₆H₄O₂), a benzene ring with two oppositely located carbonyl functional groups.

Product structure: Benzene ring with two ketone groups at the para positions.

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