Q.

Aniline is treated with excess of CH3I. The final product is

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a

C6H5NHCH3

b

C6H5N(CH3)2

c

C6H5N+(CH3)3I-

d

C6H5I

 

answer is C.

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Detailed Solution

One mole of CH3I reacts with aniline forms N-methylaniline

Two mole of CH3I reacts with aniline forms N,N-dimethylaniline

Three mole of CH3I reacts with aniline forms N,N,N-trimethyl Anilinium iodide

 

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