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Antimony pentafluoride, ${SbF}_{5}$ reacts with ${XeF}_{4}$ to form an adduct. The shapes of cation and anion in the compound are respectively.

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square pyramidal, octahedral

square planar, octahedral

Bent-T-shaped, octahedral

square planar, trigonal bipyramidal

answer is B.

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Detailed Solution

$Xe F_{4} + {SbF}_{5} \to {[{XeF}_{3}]}^{+} {[{SbF}_{6}]}^{-}$

${[{XeF}_{3}]}^{+}$ has a bent T-Shape.

${[{SbF}_{6}]}^{-}$ is octahedral.

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