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A nucleus decays by $β^{+}$ emission followed by a gamma emission. If the atomic and mass numbers of the parent nucleus are Z and A respectively,
the corresponding numbers for the daughter nucleus are respectively.

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Z - 1 and A - 1

Z + 1 and A

Z - 1 and A

Z + 1 and A - 1

answer is C.

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Detailed Solution

After $β^{+} ({}_{+ 1}e^{0})$ emission atomic number decreases by one and mass number remain unchanged. $γ$ -emission, there will be no change on mass number and atomic number.

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