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Q.

Aq. CuSO4 decolourise on addition of KCN due to formation of complex (A). In complex (A)
(i) Number of d-orbitals in hybridization is/are “a”
(ii) Charge on metal is “b”
(iii) Coordination number of central atom/ion is “c”, then find  8a+2b+c

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answer is 8.

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Detailed Solution

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 CuSO4+4KCN→K2[Cu(CN)4]+K2SO4
Complex =  [Cu(CN)4]2−
Metal charge =  2
Hybridization = sp3
∴ a= 0 (d- orbitals are not involved)
Coordination number of central atom
(c) = 4
 8a +2b+ c=8(0) +2(2)+ 4
  = 8

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