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Aqueous solution of a salt $(Y)$ is alkaline to lithmus. On strong heating, it swells-up to give a glassy material. When conc. $H_{2} S O_{4}$ is added to a hot concentrated solution of $(Y)$ , while crystals of a weak acid separate out. Hence, the compound (Y) is

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$N a_{2} S O_{4} .10 H_{2} O$

$C a_{2} P_{6} O_{11} .10 H_{2} O$

$N a_{2} B_{6} O_{11}$

$N a_{2} B_{4} O_{7} .10 H_{2} O$

answer is D.

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Detailed Solution

$N a_{2} B_{4} O_{7} + 7 H_{2} O \overset{}{\to} \underset{A l k a l i n e}{\underset{⏟}{\underset{S t r o n g b a s e}{2 N a O H} + \underset{W e a k a c i d}{4 H_{3} B O_{3}}}}$

$N a_{2} B_{4} O_{7} + 7 H_{2} O \overset{Δ}{\to} \underset{G l a s s y - b e a d}{\underset{⏟}{2 N a B O_{2} + B_{2} O_{3}}}$

$\underset{(W h i t e c r y s t a l s)}{N a_{2} B_{4} O_{7}} + H_{2} S O_{4} + 5 H_{2} O_{4} + 4 H_{3} B O_{3}$

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