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Q.

Aqueous solution of CuSO₄ is electrolysed using inert electrodes till the blue colored solution becomes colorless. The colorless solution formed is

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a

$H_{2} {SO}_{4}$

b

$Cu (OH)_{2}$

c

$H_{2} O$

d

${CuSO}_{4}$

answer is B.

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Detailed Solution

When CuSO_4(aq) are electrolysed by Pt electrode, ${CuSO}_{4 (aq)} \to {Cu}_{}^{2 +} + {SO}_{4}^{2 -} + H^{+} + {OH}^{-}$
$Cathode : {Cu}^{2 +} + 2 e^{-} \to Cu Anode : 4 {OH}^{-} \to 2 H_{2} O + O_{2} + 4 e^{-} remaning ions 2 H^{+} + {SO}_{4}^{2 -} \to H_{2} {SO}_{4}$
During electrolysis, Cu²⁺_(aq) decreases and H₂SO₄ is formed.
Hence, the blue color of of the solution gradually disappears.

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