Aqueous solution of ${\mathrm{CuCl}}_2$  is subjected to electrolysis using Pt electrodes. Then the correct statement is

${\mathrm{AqCuCl}}_2\mathrm{is}\mathrm{a}\mathrm{salt}\mathrm{of}\mathrm{SA}-\mathrm{WB}.\mathrm{It}\text{'}\mathrm{s}{\mathrm{p}}^{\mathrm{H}}<7$

On electrolysis  At Cathode
                              Discharge potential of ${\mathrm{Cu}}^{+2}\mathrm{is}\mathrm{less}\mathrm{than}{\mathrm{H}}_2\mathrm{O}$

$\therefore {\mathrm{Cu}}^{+2}+2{\mathrm{e}}^{-}\to \mathrm{Cu}$
            At Anode
                       Discharge potential of  ${\mathrm{Cl}}^{-}\mathrm{is}\mathrm{less}\mathrm{than}{\mathrm{H}}_2\mathrm{O}$
$\begin{array}{l}2{\mathrm{Cl}}^{-}\to {\mathrm{Cl}}_2+2{\mathrm{e}}^{-}\\ \therefore \mathrm{The}\mathrm{left}\mathrm{over}\mathrm{solution}\mathrm{will}\mathrm{be}{\mathrm{H}}_2\mathrm{O}\mathrm{with}{\mathrm{p}}^{\mathrm{H}}=7\\ {\mathrm{p}}^{\mathrm{H}}<7\mathrm{changes}\mathrm{to}{\mathrm{P}}^{\mathrm{H}}=7\\ {\mathrm{p}}^{\mathrm{H}}\mathrm{progressively}\mathrm{increases}\end{array}$