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Q.

Area enclosed between the curves $| y | = 1 - x^{2} and x^{2} + y^{2} = 1$ is

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a

$\frac{π - 8}{3} sq . units$

b

$\frac{3 π - 8}{3} sq . units$

c

$\frac{2 π - 8}{3} sq . units$

d

$\frac{π + 2}{3} sq . units$

answer is A.

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Detailed Solution

$A = \int_{0}^{1} (1 - x^{2}) dx = \frac{2}{3}$

Required area = area of circle –4A

$\Rightarrow π - \frac{8}{3} = \frac{3 π - 8}{3}$

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