Area enclosed by 2|x|+3|y| ≤ 6 is

x>0, y>0 x3+y2=1 ⇒ area = 4(Area of Δle)A=4×12 × 3 ×2= 12 s/units

Area enclosed by 2|x|+3|y| ≤ 6 is

x>0, y>0 x3+y2=1 ⇒ area = 4(Area of Δle)A=4×12 × 3 ×2= 12 s/units

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Area enclosed by $2 | x | + 3 | y | \leq 6$ is

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$3 s q . u n i t s$

$4 s q . u n i t s$

$12 s q . u n i t s$

$24 s q . u n i t s$

answer is C.

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Detailed Solution

$x > 0, y > 0 \frac{x}{3} + \frac{y}{2} = 1$ $\Rightarrow$ area = $4 (A r e a o f Δ l e)$

$A = 4 \times \frac{1}{2} \times 3 \times 2$

$= 12 s / u n i t s$

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Area enclosed by 2|x|+3|y| ≤ 6 is

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Area enclosed by $2 | x | + 3 | y | \leq 6$ is