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Q.

Area (in sq. units) of the region outside |x|2+|y|3=1 and inside the ellipse x24+y29=1 is.

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a

3(π2)

b

6(π2)

c

3(4π)

d

6(4π)

answer is A.

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Detailed Solution

Area of the ellipse x24+y29=1 is πab=π(2)(3)=6π

Area of the rhombus formed of |x|2+|y|3=1 is 12(4)(6)=12

Area enclosed by the region given of |x|2+|y|31 and x24+y291 is 

6π12=6(π2)

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