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Arrange the following carbanions in decreasing order of stability:
$\underset{(I)}{^{Θ} {CH}_{2} - Cl}$ $\underset{(II)}{^{Θ} {CH}_{2} - CN}$ $\underset{(III)}{^{Θ} {CH}_{2} - {NO}_{2}}$ $\underset{(IV)}{^{Θ} {CH}_{2} - {CH}_{3}}$

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III > II > IV > I

III > II > I > IV

III > I > II > IV

II > III > I > IV

answer is B.

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