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Arrange the following carbanions in decreasing order of stability

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IV > III > I > II

I > II > IV > III

IV > III > II > I

II > I >III > IV

answer is D.

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Detailed Solution

In I and II -sp-hybridized carbon atom is more electronegative than sp³
-hybridized carbon atom and hence, can accommodate the negative charge more effectively.

−CH₃ group has +I effect, therefore, it means decrease in the negative charge and hence, destabilises the carbanion.

The order of EN is sp>sp2>sp3.
.

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