Arrange the following compound in increasing order of polarity

$\mathrm{polarity} \mathrm{\alpha } \mathrm{\mu } \mathrm{\alpha } \mathrm{aromaticity}$

Compound II is anti-aromatic due to the presence of $4\mathrm{\pi }$electrons.

Compound I is non-aromatic.

Compound III is aromatic with $2\mathrm{\pi }$ electrons. Hence, it is aromatic.

So, the order of polarity is: II < I < III.