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Arrange the following compounds in the order of increasing number of molecules: $2 g {NH}_{3}; 2 g H_{2} O; 2 g CO; 2 g of HCl$

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$HCl < CO < H_{2} O < {NH}_{3}$

$CO < HCl < H_{2} O < {NH}_{3}$

${NH}_{3} < H_{2} O < HCl < CO$

${NH}_{3} < H_{2} O < CO < HCl$

answer is B.

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Detailed Solution

2 g of ${NH}_{3} - 0 .117 N_{A}$ molecules
2 g of ${NH}_{3} - 0 .117 N_{A}$ molecules
2 g of $CO - 0 .07 N_{A}$ molecules
2 g of $HCl - 0 .05 N_{A}$ molecules

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