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Arrange the following cyano complexes in increasing order of magnetic moment

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${[Fe (CN)_{6}]}^{4 -} < {[Fe (CN)_{6}]}^{3 -} < {[Mn (CN)_{6}]}^{3 -} < {[Cr (CN)_{6}]}^{3 -}$

${[Fe (CN)_{6}]}^{3 -} < {[Cr (CN)_{6}]}^{3 -} < {[Mn (CN)_{6}]}^{3 -} < {[Fe (CN)_{6}]}^{4 -}$

${[Mn (CN)_{6}]}^{3 -} < {[Fe (CN)_{6}]}^{3 -} < {[Fe (CN)_{6}]}^{4 -} < {[Cr (CN)_{6}]}^{3 -}$

${[Fe (CN)_{6}]}^{3 -} < {[Cr (CN)_{6}]}^{3 -} < {[Fe (CN)_{6}]}^{4 -} < {[Mn (CN)_{6}]}^{3 -}$

answer is A.

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Detailed Solution

$Number of unpaired electrons (a) {[Fe (CN)_{6}]}^{4 -} 0 (t_{2 g}^{6} e_{g}^{0}) (b) {[Fe (CN)_{6}]}^{3 -} 1 (t_{2 g}^{5} e_{g}^{0}) (c) {[Mn (CN)_{6}]}^{3 -} 2 (t_{2 g}^{4} e_{g}^{0}) (d) {[Cr (CN)_{6}]}^{3 -} 3 (t_{2 g}^{3} e_{g}^{0})$

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