Arrange the following elements in the increasing order of number of unpaired electrons in it.
A) Sc   B) Cr    C) V    D) Ti   E)Mn
Choose the correct answer from the options given below:
 

$$\begin{gathered} \mathrm{Sc}\left(21\right):\left[\mathrm{Ar}\right]4{\mathrm{s}}^{2}3{\mathrm{d}}^1\to \mathrm{One} \mathrm{unpaired} \mathrm{electron}-\mathrm{A} \\ \mathrm{Cr}\left(24\right):\left[\mathrm{Ar}\right]4{\mathrm{s}}^{1}3{\mathrm{d}}^5\to \mathrm{Six} \mathrm{unpaired} \mathrm{electrons}-\mathrm{B} \\ \mathrm{V}\left(23\right):\left[\mathrm{Ar}\right]4{\mathrm{s}}^{2}3{\mathrm{d}}^{3-}\to \mathrm{Three} \mathrm{unpaired} \mathrm{electrons}-\mathrm{C} \\ \mathrm{Ti}\left(22\right):\left[\mathrm{Ar}\right]4{\mathrm{s}}^{2}3{\mathrm{d}}^2\to \mathrm{Two} \mathrm{unpaired} \mathrm{electrons}-\mathrm{D} \\ \mathrm{Mn}\left(25\right):\left[\mathrm{Ar}\right]4{\mathrm{s}}^{2}3{\mathrm{d}}^5\to \mathrm{Five} \mathrm{unpaired} \mathrm{electrons}-\mathrm{E} \\ \therefore \mathrm{A}<\mathrm{D}<\mathrm{C}<\mathrm{E}<\mathrm{B} \end{gathered}$$