Arrange the following fractions in ascending order: $\frac{5}{11}, \frac{7}{11}, \frac{2}{11}, \frac{6}{11}$

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$\frac{2}{11} < \frac{5}{11} < \frac{6}{11} < \frac{7}{11}$

$\frac{7}{11} < \frac{6}{11} < \frac{5}{11} < \frac{2}{11}$

$\frac{7}{11} < \frac{2}{11} < \frac{6}{11} < \frac{5}{11}$

$\frac{2}{11} < \frac{6}{11} < \frac{7}{11} < \frac{5}{11}$

answer is D.

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Detailed Solution

The given fractions $\frac{5}{11}, \frac{7}{11}, \frac{2}{11}, \frac{6}{11}$ are like fractions.

When the denominator of each fraction is the same, the fraction with the greater numerator is greater in value.

So, 2 < 5 < 6 <7

Hence, $\frac{2}{11} < \frac{5}{11} < \frac{6}{11} < \frac{7}{11}$ .

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