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Arrange the following fractions in ascending order:
$\frac{3}{4}, \frac{3}{5}, \frac{3}{11}, \frac{3}{2}, and \frac{3}{13}$ .

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$\frac{3}{2} < \frac{3}{4} < \frac{3}{5} < \frac{3}{11} < \frac{3}{13}$

$\frac{3}{2} < \frac{3}{11} < \frac{3}{4} < \frac{3}{5} < \frac{3}{13}$

$\frac{3}{13} < \frac{3}{11} < \frac{3}{5} < \frac{3}{4} < \frac{3}{2}$

$\frac{3}{4} < \frac{3}{5} < \frac{3}{11} < \frac{3}{13} < \frac{3}{2}$

answer is B.

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Detailed Solution

The given fractions are $\frac{3}{4}, \frac{3}{5}, \frac{3}{11}, \frac{3}{2}, and \frac{3}{13}$ .

When the numerators are the same, the fraction with a greater denominator is smaller in value.

So, 13 > 11 > 5 > 4 > 2

Therefore the ascending order of the fraction is $\frac{3}{13} < \frac{3}{11} < \frac{3}{5} < \frac{3}{4} < \frac{3}{2}$ .

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