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Q.

Arrange the following in correct increasing order of P^Ka
$(I) {CH}_{3} - {CH}_{2} - {CH}_{2} - OH$

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a

$IV < III < I < II$

b

$II < II < IV < I$

c

$I < II < III < IV$

d

$IV < III < II < I$

answer is A.

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Detailed Solution

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Compound IV has high acidic character because of the charge delocalization on the benzene ring.
Compound III has -CH₂ group attached to the benzene ring, making -CH₂ group slightly electron deficient and increases the polarity of O-H bond.
Primary alcohols are more acidic than secondary alcohols as less carbon atoms are attached to the alpha carbon.
So, Compound I is more acidic than Compound II.
So, the order of p^ka values is: IV < III < I <II

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Arrange the following in correct increasing order of PKa (I) CH3−CH2−CH2−OH