Arrange the following in increasing order of lattice energy ${MgF}_{2}, {CaF}_{2}, {ZrO}_{2}$ :

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MgF2>CaF2>ZrO2

ZrO2>MgF2>CaF2

ZrO2>CaF2>MgF2

CaF2>MgF2>ZrO2

answer is B.

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Detailed Solution

$\begin{array}{rcr} {ZrO}_{2} & {MgF}_{2} & {CaF}_{2} \\ + 4, 2 (- 2) & + 2, 2 (- 1) & + 2, 2 (- 1) \\ = 4 \times 4 & = 2 \times 2 & = 2 \times 2 \\ = 16 & = 4 & = 4 \end{array}$

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$∴ {ZrO}_{2} > {MgF}_{2} > {CaF}_{2}$

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