Arrange the following in the increasing order of deviation from normal tetrahedral angle :

${\mathrm{sp}}^3$ hybridization is present in every molecule. ${\mathrm{P}}_4$contains one core $\mathrm{P}$ atom with one lone pair and is surrounded by larger $3\mathrm{P}$ ligands, each of which has a single lone pair. The core $\mathrm{P}$ atom of ${\mathrm{PH}}_3$ likewise possesses one lone pair. However, because the $\mathrm{H}$ atoms are smaller, they will be less attracted to lone pairs. The center $\mathrm{O}$ atom in ${\mathrm{H}}_2\mathrm{O}$ also has two lone pairs. Due to the existence of lone pairs, all of these molecules are deviant. The tetrahedral angle's order of deviance

${\mathrm{H}}_2\mathrm{O} < {\mathrm{PH}}_3 < {\mathrm{P}}_4$