Questions

# Arrange the following in the order of increasing mass. (Atomic mass of $\text{O}=16\text{u},\text{\hspace{0.17em}\hspace{0.17em}Cu}=63\text{u},\text{\hspace{0.17em}\hspace{0.17em}N}=14\text{u}$ )I) One atom of oxygen    II) one atom of nitrogen    III)  $1×{10}^{-10}$  mole of oxygen gas    IV) $1×{10}^{-10}$ mole of copper

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a
$\text{II}<\text{I}<\text{III}<\text{IV}$
b
$\text{I}<\text{II}<\text{III}<\text{IV}$
c
$\text{III}<\text{II}<\text{IV}<\text{I}$
d
$\text{IV}<\text{II}<\text{III}<\text{I}$

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detailed solution

Correct option is A

Single atom of nitrogen has the mass 14 u but single atom of oxygen has 16u as mass. Hence, II < I. In the similar way, $1×{10}^{-10}$ mol of copper has greater atomic mass than $1×{10}^{-10}$ mol of oxygen. Hence, III  < IV.

Therefore, overall increasing order of atomic mass is $\text{II}<\text{I}<\text{III}<\text{IV}$