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Arrange the following oxides in the increasing order of acidic nature and number each oxide giving ‘1’ to lowest acidic oxide then increasing number by one integral step towards higher acidic oxide which gets ‘4’. What is the sum of maximum covalencies of all different elements of oxides that takes numbers 2 & 3?
$C O_{2}, N_{2} O_{5}, S i O_{2}, S O_{3}$

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answer is 12.

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Detailed Solution

$\underset{1}{S i O_{2}}, \underset{2}{C O_{2}}, \underset{3}{N_{2} O_{5}}, \underset{4}{S O_{3}}$

$2 : C O_{2} C \to 4 O \to 4$

$3 : N_{2} O_{5} N \to 4$

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