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Q.

Arrange the following
 CH3CH2CH2Cl(I), CH3CH2–CHCl–CH3 (II),
 (CH3)2CHCH2Cl (III) and (CH3)3C –Cl (IV) in order of decreasing tendency towards SN 2 reaction

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a

I > III > II > IV

b

III > IV > II > I

c

II > I > III > IV

d

IV > III > II > I

answer is A.

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Detailed Solution

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In SN2​ reactions, the attack of nucleophile occurs from the back side on the carbon atom carrying the halogen. Therefore, presence of bulky substituents on or near this carbon atom tends to hinder the approach of the nucleophile to the a-carbon due to steric hindrance and thus makes the reaction difficult to occur. Thus, the reactivity in SN2​ reactions follows the following order
CH3​CH2​CH2​Cl(I)>(CH3​)2​CHCH2​Cl(III)>CH3​−CH2​−CHCl−CH3​(II)>(CH3​)3​C−Cl(IV).

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Arrange the following CH3CH2CH2Cl(I), CH3CH2–CHCl–CH3 (II), (CH3)2CHCH2Cl (III) and (CH3)3C –Cl (IV) in order of decreasing tendency towards SN 2 reaction