Arrange the fractions $\frac{1}{2},\frac{3}{4},\frac{5}{8},\frac{3}{8}$ in ascending order.

The given fractions are $\frac{1}{2},\frac{3}{4},\frac{5}{8},\frac{3}{8}$.

LCM of 2, 4 and 8 is 8.

Now make the fraction's denominator 8.

$\begin{array}{c}\frac{1}{2}=\frac{1\times 4}{2\times 4}=\frac{4}{8},\end{array}$

$\frac{3}{4}=\frac{3\times 2}{4\times 2}=\frac{6}{8},$

$\frac{5}{8} \mathrm{and} \frac{3}{8}$

If the denominator for the two fractions are the same, then the fraction with a larger numerators is the greater fraction.

$\begin{array}{c}\therefore \frac{3}{8}<\frac{4}{8}<\frac{5}{8}<\frac{6}{8}\\ \end{array}$

$\Rightarrow \frac{3}{8}<\frac{1}{2}<\frac{5}{8}<\frac{3}{4}$