Arrange the vectors additions so that their magnitudes are in the increasing order
a) two vector $\vec{A} a n d \vec{B}$ are parallel
b) Two vectors $\vec{A} a n d \vec{B}$ are anti parallel
c) Two vectors $\vec{A} a n d \vec{B}$ making an angle 60°
d) Two vectors $A a n d \vec{B}$ making 120°.

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a, c, d, b

b, c, d, a

c, d, a, b

b, d, c, a

answer is A.

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Detailed Solution

$R = \sqrt{A^{2} + B^{2} + 2 A B \cos θ}$

$I f θ = 0 t h e n R = A + B$

$I f θ = 60 t h e n R = \sqrt{A^{2} + B^{2} + 2 A B \cos 60} = = \sqrt{A^{2} + B^{2} + A B}$

$I f θ = 120 t h e n R = \sqrt{A^{2} + B^{2} + 2 A B \cos 120} = = \sqrt{A^{2} + B^{2} - A B}$

$I f θ = 180 t h e n R = A - B$

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