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Q.

As per given figure, a weightless pulley P is attached on a double inclined frictionless surface. The tension in the string (massless) will be (if g = 10 m/s2)
 

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a

(43+1)N

b

4(3-1)N

c

4(3+1)N

d

(43-1)N

answer is D.

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Detailed Solution

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4032T=4a  

T102=a

a=431

So, T=2034(431)

=43+4

T=4(3+1)

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