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Q.

As per this diagram a point charge +q is placed at the origin O. Work done in taking another point charge –Q from the point A [co-ordinates (0,a)] to another point B [co-ordinates (a,0)] along the straight path AB is

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a

zero

b

qQ4πε01a2⋅a2

c

qQ14πε0a2 2a

d

−qQ14πε0a22a

answer is A.

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Detailed Solution

Potential at A& B are same. Potential difference is zero, then  work done is zero

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