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As shown in figure, a 70 kg garden roller is pushed with a force of $\vec{F} = 200 N$ at an angle of $30^{\circ}$ with horizontal. The normal reaction on the roller is (Given $g = 10 m s^{- 2})$

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600 N

800 N

$800 \sqrt{2} N$

$200 \sqrt{3} N$

answer is A.

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Detailed Solution

Consider the F.B.D of the roller with F resolved in vertical and horizontal components.

To balance the forces in the vertical direction

$\begin{array}{l} \Rightarrow N = mg + Fsin 30^{0} \\ ∴ N = 800 N \end{array}$

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