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As shown in figure, region BCDEF and ABFG are of refractive index 2.0 and 1.5 respectively. A particle `o` is kept at the mid of region BCEF. Final image of the object as seen by the eye is at a distance of ..... (Curved part is a spherical one of radius 10cm)

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30cm from point D

40cm from point D

20cm from point D

22.5cm from point D

answer is A.

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Detailed Solution

$\frac{μ_{2} - μ_{1}}{R} = \frac{μ_{2}}{v} - \frac{μ_{1}}{u}$

$\Rightarrow \frac{1 - 2}{- 10} = \frac{1}{v} - \frac{2}{- 15}$

$\Rightarrow v = - 30 cm$

The image formed by refraction at spherical surface is formed in the region of ABFG.

Here only one refraction at spherical surface will take place.

Hence, final image will be seen at 30 cm from point D inside the region ABFG.

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