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As shown in figure value of inductive reactance $X_{L}$ will be

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$40 Ω$

$30 Ω$

$50 Ω$

$20 Ω$

answer is C.

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Detailed Solution

$V = I \sqrt{{(20 + 10)}^{2} {(X_{L} + X_{L} - C_{c_{2}})}^{2}} 100 = 2 \sqrt{{(30)}^{2} + {(30 + X_{L} - 40)}^{2}} {(50)}^{2} = {(30)}^{2} + {(X_{L} - 10)}^{2} {(X_{L} - 10)}^{2} = 80 \times 20; X_{L} - 10 = 40; X_{L} = 50 Ω$

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