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Q.

As shown in the figure, a metallic rod of linear density 0.45 kg m–1 is lying horizontally on a smooth inclined plane which makes an angle of 45° with the horizontal. The minimum current flowing in the rod required to keep it stationary, when 0.15 T magnetic field is acting on it in the vertical upward direction, will be : {Use g = 10 m/s2}
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a

3 A

b

10 A

c

30 A

d

15 A

answer is A.

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Detailed Solution

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mg×sin45o=ilB×cos45omg×12=ilB2 i=mgBl=0.45×100.15=30A

 

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