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As shown in the figure, a plane mirror is fixed at a height of 50cm from the bottom of tank containing water $(μ = \frac{4}{3})$ . The height of water in the tank is 8cm. A small bulb is placed at the bottom of the water tank. The distance of image of the bulb formed by mirror from the bottom of the tank is __________cm.

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answer is 98.

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Detailed Solution

$shift (s) = 8 [1 - \frac{1}{μ}] = 8 [\frac{1}{4}] = 2 cm$
$∴$ Distance of image from mirror is 48 cm and from the bottom of the tank is 98 cm

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