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Q.

As shown in the figure, a point charge Q is placed at the centre of conducting spherical shell of inner radius a and outer radius b. The electric field due to charge Q in three different regions I, II and III is given by:
(I: r<a, II: a<r<b, III: r>b)

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a

E_I $\neq$ 0, E_II= 0, E_III = 0

b

E_I= 0, E_II= 0, E_III = 0

c

E_I $\neq$ 0, E_II= 0, E_III $\neq$ 0

d

E_I= 0, E_II= 0, E_III $\neq$ 0

answer is B.

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Detailed Solution

detailed_solution_thumbnail

using Gauss law, $\int \vec{E} \cdot d \vec{s} = \frac{1}{ϵ 0} (q_{enclosed})$
$\begin{array}{l} I . r <\Rightarrow q_{enclosed} = q \Rightarrow E_{I} \neq 0 \\ II . a < r < b \Rightarrow q_{enclosid} = 0 \Rightarrow E_{II} = 0 \\ III . r > b \to q_{endosed} = q \Rightarrow E_{III} \neq 0 \end{array}$

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