As shown in the figure, there identical polaroids P1, P2 and P3 are placed one after another. The pass axis of P2 and P3 are inclined at angle of 60° and 90° with respect to axis of P1 . The source S has and intensity of 256Wm2. The intensity of light at point O is ______Wm2.

Les I0 be intensity of source S∴ After P1,I1=I02After P2,I2=I02cos2⁡60∘=I08After P3,I3=I08cos2⁡30∘=3I032=332×256=24W/m2

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

As shown in the figure, there identical polaroids P₁, P₂and P₃ are placed one after another. The pass axis of P₂ and P₃ are inclined at angle of 60° and 90° with respect to axis of P₁ . The source S has and intensity of $256 \frac{W}{m^{2}}$ . The intensity of light at point O is ______ $\frac{W}{m^{2}}$ .

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

answer is 24.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Les I₀ be intensity of source S
$∴ After P_{1}, I_{1} = \frac{I_{0}}{2}$
After $P_{2}, I_{2} = \frac{I_{0}}{2} \cos^{2} 60^{\circ} = \frac{I_{0}}{8}$
After $P_{3}, I_{3} = \frac{I_{0}}{8} \cos^{2} 30^{\circ} = \frac{3 I_{0}}{32} = \frac{3}{32} \times 256 = 24 W / m^{2}$