A+SOCl2⟶B+SO2+HCl X+Na⟶C+H2 B+C⟶(C2H5)2O+NaClThen A and X are respectively

Given:- It is given to find A and X in the reactions.Explanation:-The given reactions are completed as below. Et−OH+SOCl2⟶EHa+SO2+HCl Et−OH+Na⟶EHONa+12 H2 EtCl+EtONa⟶(Et)2O+NaClHence, the correct answer is option (C) C2H5OH and C2H5OH.

A+SOCl2⟶B+SO2+HCl X+Na⟶C+H2 B+C⟶(C2H5)2O+NaClThen A and X are respectively

Given:- It is given to find A and X in the reactions.Explanation:-The given reactions are completed as below. Et−OH+SOCl2⟶EHa+SO2+HCl Et−OH+Na⟶EHONa+12 H2 EtCl+EtONa⟶(Et)2O+NaClHence, the correct answer is option (C) C2H5OH and C2H5OH.

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$\begin{aligned} A + {SOCl}_{2} ⟶ B + {SO}_{2} + HCl \\ X + Na ⟶ C + H_{2} \\ B + C ⟶ {(C_{2} H_{5})}_{2} O + NaCl \end{aligned}$
Then A and X are respectively

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$C_{2} H_{5} CI and C_{2} H_{5} ONa$

$C_{2} H_{5} ONa and C_{2} H_{5} Cl$

$C_{2} H_{5} OH and C_{2} H_{5} OH$

$C_{2} H_{5} OH and C_{2} H_{5} ONa$

answer is C.

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Detailed Solution

Given:- It is given to find A and X in the reactions.

Explanation:-

The given reactions are completed as below.

$\begin{aligned} Et - OH + {SOCl}_{2} ⟶ EHa + {SO}_{2} + HCl \\ Et - OH + Na ⟶ EHONa + \frac{1}{2} H_{2} \\ EtCl + EtONa ⟶ {(Et)}_{2} O + NaCl \end{aligned}$