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Q.

A ${sp}^{3}$ hybridized orbital contains

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a

$\frac{2}{3}$ -character

b

$\frac{1}{4}$ -character

c

$\frac{3}{4}$ -character

d

$\frac{1}{2}$ -character

answer is A.

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Detailed Solution

In ${sp}^{3}$ -hybridization each ${sp}^{3}$ hybridized orbital has 1/4 s-character.

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