Aspirin is a pain reliever with pK_a = 2.
Two tablets each containing 0.09 g of aspirin are dissolved in 100 mL solution. pH will be

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1.0

2.0

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answer is D.

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Detailed Solution

$Aspirin is a weak acid = 0 .09 \times 2 g / 100 mL = 1 .8 {gL}^{- 1} \frac{1 .8}{180} mol L^{- 1} = 0 .01 M pH (weak acid) = \frac{1}{2} [{pK}_{a} - \log C] = \frac{1}{2} [2 + 2] = 2$

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