Assertion (A ) : The roots of the equation $a\left(b-c\right)x^2+b\left(c-a\right)x+c\left(a-b\right)=0$ are 1,$\frac{c\left(a-b\right)}{a\left(b-c\right)}$

Reason (R ) : If a+b+c=0  then the roots of $x^2+bx+c=0$ are 1,$\frac{c}{a}$

Assertion (A ) : Given Equation$a\left(b-c\right)x^2+b\left(c-a\right)x+c\left(a-b\right)=0$

Here sum of co.eff is zero

             Clearly ‘1’ is a root

            Let another root is $\beta$

            Then by using product of roots $\beta =\frac{c\left(a-b\right)}{a\left(b-c\right)}$

(A ) is true

            Reason ( R)_: is True

            Both A and R are True and R explain Assertion.

            ANS: ( 1 )